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Algebra 21 Online
OpenStudy (dannyrod2000):

C(t)=5t-200 inverse function A. T(c)= c+5/200 B. T(c)= c-5/200 C. T(c)= c-200/5 D. T(c)= c+200/5

jimthompson5910 (jim_thompson5910):

Swap t and C(t). Then solve for C(t) C(t)=5t-200 t =5*C(t)-200 solve for C(t)

OpenStudy (dannyrod2000):

can you explain a little more please @jim_thompson5910

jimthompson5910 (jim_thompson5910):

think of C(t) as another variable call it z if you want

jimthompson5910 (jim_thompson5910):

t = 5z - 200 solve for z

jimthompson5910 (jim_thompson5910):

so isolate that on one side

OpenStudy (dannyrod2000):

would it be C?

jimthompson5910 (jim_thompson5910):

how would you move that -200 over?

OpenStudy (dannyrod2000):

B?

OpenStudy (dannyrod2000):

@jim_thompson5910 ?

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