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Algebra
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C(t)=5t-200 inverse function A. T(c)= c+5/200 B. T(c)= c-5/200 C. T(c)= c-200/5 D. T(c)= c+200/5
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Swap t and C(t). Then solve for C(t) C(t)=5t-200 t =5*C(t)-200 solve for C(t)
can you explain a little more please @jim_thompson5910
think of C(t) as another variable call it z if you want
t = 5z - 200 solve for z
so isolate that on one side
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would it be C?
how would you move that -200 over?
B?
@jim_thompson5910 ?
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