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A worker pushes a wheelbarrow up a slope with a force of 100 pounds. The slope has an angle of 15° with the horizontal. Express the force vector F in terms of i and j, where i is the force vector of magnitude 1 pound pointing along the hoizontal component of the worker's direction, and j is the vector of magnitude 1 pound pointing upwards i know that: Horizontal force = 100 cos 15° = 96.6 Vertical force = 100 sin 15° = 25.9 but i need to express the F vector in terms of i and j
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i think 96.6i+25.9j
i did that, but apparently thats not that answer
oh wait i ment to round it of to two decimals, thanks for the help though
:)
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