plse solve it.. its tan(x-pie/2)*cos(3pi/2+x)-sin^3(7pi/2-x)/cos(x-pi/2)*tan(3pi/2+x)
simplifies to
a.(1+cos^2x)
b.sin^2x
c.-(1+cos^2x)
d.cos^2x

Question

plse solve it.. its tan(x-pie/2)*cos(3pi/2+x)-sin^3(7pi/2-x)/cos(x-pi/2)*tan(3pi/2+x)
simplifies to
a.(1+cos^2x)
b.sin^2x
c.-(1+cos^2x)
d.cos^2x

anonymous · Answer

plseee helppp

adunb8 · Answer

try wolfram alpha xp

anonymous · Answer

@adunb8
who is wolfram alpha xp

adunb8 · Answer

anonymous · Answer

$$\tan(x-\pi/2)*\cos(3\pi/2+x)-\sin^3(7\pi/2-x)/\cos(x-\pi/2)*\tan(3\pi/2=x)$$

anonymous · Answer

Have they given you the formula to find sin^3(7pi/2-x)???

amoodarya · Answer

sin(7pi/2-x) = sin(7pi/2) cos(x) - cos(7pi/2) sin(x)
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