Question

plse solve it.. its tan(x-pie/2)*cos(3pi/2+x)-sin^3(7pi/2-x)/cos(x-pi/2)*tan(3pi/2+x)
simplifies to
a.(1+cos^2x)
b.sin^2x
c.-(1+cos^2x)
d.cos^2x

Answer 1

plseee helppp

Answer 2

try wolfram alpha xp

Answer 3

@adunb8
who is wolfram alpha xp

Answer 4

https://www.wolframalpha.com/input/?i=tan%28x-pie%2F2%29*cos%283pi%2F2%2Bx%29-sin%5E3%287pi%2F2-x%29%2Fcos%28x-pi%2F2%29*tan%283pi%2F2%2Bx%29

Answer 5

\[\tan(x-\pi/2)*\cos(3\pi/2+x)-\sin^3(7\pi/2-x)/\cos(x-\pi/2)*\tan(3\pi/2=x)\]

Answer 6

Have they given you the formula to find sin^3(7pi/2-x)???

Answer 7

sin(7pi/2-x) = sin(7pi/2) cos(x) - cos(7pi/2) sin(x)