Question

INTEGRATE 1/(1-x)

Answer 1

let
1-x=z

Answer 2

-dx=dz

Answer 3

dz=-dx

Answer 4

and x=1-z

Answer 5

no

Answer 6

i did all , but i just can't seem to get the answer somehow

Answer 7

-integrate(dz/z)
=-ln(z)

Answer 8

it is the log

Answer 9

put the value of z

Answer 10

\[\int\limits_{}^{}\frac{ 1-z }{ z}\]
\[\int\limits_{}^{}\frac{ 1 }{ z}-1\]

Answer 11

\[\ln z -z +c\]

Answer 12

\[-[\ln(1-x)-1+x+c]\]

Answer 13

this is what i am getting but wolfram has something which i can't connect to this

Answer 14

@shamim this what i did. please correct.

Answer 15

hope it helps

Answer 16

From Mathematica.\[\frac{\partial (-\log (1-x))}{\partial x}=\frac{1}{1-x} \]