Question

Find the area of a regular nonagon with a side length of 9 and an apothem of 16.

Answer 1

\[A=\frac{ap}{2}\]
where \(A\) is the area, \(a\) is the length of the apothem, and \(p\) is the perimeter. In this case, since you have a nonagon, \(p=9s\), where \(s\) is the length of any one side.
\[A=\frac{16\cdot9\cdot9}{2}=\cdots\]

Answer 2

649? @SithsAndGiggles