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In the figure below, ∠DEC ≅ DCE, ∠B ≅ ∠F, and segment DF is congruent to segment DB. Point C is the point of intersection between segment AG and segment BD, while point E is the point of intersection between segment AG and segment DF. Prove ΔABC ≅ ΔGFE
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<B=<F ( given) CB=EF (proved) <ACB=<GEF ( proved ) so u have 2 angle and a side btw (Angle,Side ,Angle) which is calld ASA So by ASA( (Angle,Side ,Angle)) ΔABC ≅ ΔGFE
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