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find the range of y=-cosx+3 when x is between 0 and pi
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Cos(0)=1 Cos(180)=1 the rest are fractions smaller than 1.
my bad, cos(180)=-1
oh okay i got it!
So, \(\large\color{black}{ \bf y=-cos(0)+3 =-(1)+3=2 }\) \(\large\color{black}{ \bf y=-cos(180)+3 =-(-1)+3=4 }\) you won't get cosine that is \(\large\color{black}{ \bf >│1│ }\)
I mean any other cosine.
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