Question

Find the standard equation and graph of a parabola that matches the given set of characteristics
Vertex (0,0)
Focus (4,0)

Answer 1

standard equation can be written as
(y-k)^2=4p(x-h)
where h,k is the coordinate of the vertex

Answer 2

now distence between focus and vertex is=16
so 4p=16
p=4
so equation of the parabola
y^2=4px
Y^2=16x
it will look like