an ellipse of eccentricity [2sqrt(2)]/3 is inscribed in a circle and a point within the circle is chosen at random.what is the probability that the point lies outside the ellipse

Question

amistre64 · Answer

do you recall what the eccentricity measures?

amistre64 · Answer

e = c/a .... focal length in terms of vertex length

amistre64 · Answer

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sidsiddhartha · Answer

yeah 
its$$\sqrt{(1-\frac{ b ^{2} }{ a ^{2}}}$$

amistre64 · Answer

the area of the circle if pi a^2

sidsiddhartha · Answer

yeah if a=b then its pia^2 then?

amistre64 · Answer

if a=b its a circle, and e=1

amistre64 · Answer

the circle that the ellipse is drawn inside of has a radius of a

sidsiddhartha · Answer

yeah ok

amistre64 · Answer

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amistre64 · Answer

P(inside ellipse) = area ellipse/ area circle

so 1- that is outside the ellipse