Question

Solve the following system of equations using substitution.

u = 6 + t
36 = 2t + u
A.t = 16, u = 22
B.t = 14, u = 20
C.t = 10, u = 16
D.t = 10, u = 4

Answer 1

In the second equation, you can write:
u=36-2t

Thus equating the 1st and second equation:
6 + t = 36 - 2t
t + 2t = 36 - 6
3t = 30
t = 10

Since t = 10, substitute this value into one of the equations, say the first one:

u = 6 + t
u = 6 + 10
u = 16