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f(x)=x^2 - x- 6 determine the x- intercepts of the quadratic function i think it (2,0)(-3,0)
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How did you get that?
To get x - intercepts you let y = 0 (in this case f(x) = 0).
x^2 +x - 6 = 0 x^2 +3x -2x -6 = 0 x(x+3) -2(x+3) = 0 (X-2)(x+3)= 0 answer = (2,0)(-3,0)
that how i got the answer did i do it right?
(x-3)(x+2)
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ok i see what did wrong thank you for all your help
np
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