Question

(ALGEBRA) If px2 - mx - c = 0, what is x equal to?

Answer 1

if \[ax^2+bx+c=0\] then \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 2

put \(a=p,b=-m,c=-c\)

Answer 3

if it is not clear what the answer is, let me know and i will write it

Answer 4

I am confused by all of this subject matter

Answer 5

it is a matter of substituting one set of variables for another
there is no content here at all

Answer 6

\[\huge x=\frac{-\color{blue}b\pm\sqrt{\color{blue}b^2-4\color{red}a\color{green}c}}{2\color{red}a}\]

Answer 7

in this case
\[\huge \color{red}a=\color{red}p,
\color{blue}b=\color{blue}{-m}, \color{green}c=\color{green}{-c}\]

Answer 8

when you substitute you get
\[\large x=\frac{m\pm\sqrt{m^2+4pc}}{2p}\]