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dy/dx = x+1 / y separable equation
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\[\frac{dy}{dx} = \frac{x+1}{y}\]
\[y dy = (x+1) dx\]
\[\frac{1}{2} y^2 = \frac{1}{2}x^2+x+C\]
That is correct!
\[y^2 = x^2+2x+2C\]
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correct...
\[y = \sqrt{x^2+2x+2c}\] with the plus minus stuff can't do it in latex
C is as good an arbitrary constant as 2C
`\(\pm\)` \(\pm\)
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