Question

What is the equation of a line that passes through (7, 8) and has a slope of -3?

y=−3x+29

y=3x+13

y=1/3x−29

y=−1/3x−13

Answer 1

y = mx + b
slope(m) = -3
(7,8)...x = 7 and y = 8
now we sub and solve for b
8 = -3(7) + b
8 = -21 + b
21 + 8 = b
29 = b

so our equation is : y = -3x + 29