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Solve the triangle. A = 51°, b = 11, c = 7
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hi campbell c:
|dw:1400616950881:dw|
find a using the law of cosines \[a^2 = 7^2 + 11^2 - 2 \times 7 \times 11 \times \cos(51)\] then find the angle B using the law of sines \[\frac{\sin(B}{11} = \frac{\sin(51)}{a}\] hope it helps
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okay so then a=8.5 C=39 and B= 90 right?
its all makes sense to me
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