Question

Find the area of the surface generated by rotating the graph of f(x) = sqrt(25-x^2) about the x-axis from x=3 to to x=5

Answer 1

it's just the same types of questions over and over again
if its just between 1 equation and the x-axis
you get
pi times integral from x=(lower number) to x=(higher number) of (equation)^2 dx

so for this it would become
pi times integral from 3 to 5 of (sqrt(25-x^2))^2 dx

which you can just copy and paste into http://www.wolframalpha.com/

Answer 2

52p/3

Answer 3

i might be wrong

Answer 4

it's what I got :)

Answer 5

i think it's wrong lol

Answer 6

:(

Answer 7

http://www.wolframalpha.com/input/?i=pi+times+integral+from+3+to+5+of+%28sqrt%2825-x%5E2%29%29%5E2+dx

Answer 8

can lovely chick confirm?

Answer 9

@lovelychick13

Answer 10

wat up? oh.. i see! let meh look....

Answer 11

omg i just got another tag! yes i belive that that is right jeff i gotta run doe:)

Answer 12

http://www.wolframalpha.com/input/?i=2pi+times+integral+from+3+to+5+of+%28%28sqrt%2825-x%5E2%29%29sqrt%281%2B%28-x%2Fsqrt%2825-x%5E2%29%29%5E2%29%29+dx

Answer 13

this one is good! <3