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Solve 3x^2 + x + 10 = 0. Round solutions to the nearest hundredth. x ≈ -2.83 and x ≈ 0.83 No real solutions x ≈ -2.01 and x ≈ 1.67 x ≈ -1.67 and x ≈ 2.01
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@wio
This is a quadratic polynomial so you will have to use the quadratic equation to solve for x
Do you remember the quadratic equation?
no im sorry
\[x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
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\[ax^2+bx+c\]
That is the form that your polynomial is in
so how do i solve it?
You use the values of a, b, and c in your quadratic equation and plug thenm into the quadratic formula
ok, hold on a sec.
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x=-10+ then the symbol 10^2-4, thats all can figure out..
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