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Mathematics 15 Online
OpenStudy (anonymous):

Solve 3x^2 + x + 10 = 0. Round solutions to the nearest hundredth. x ≈ -2.83 and x ≈ 0.83 No real solutions x ≈ -2.01 and x ≈ 1.67 x ≈ -1.67 and x ≈ 2.01

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

This is a quadratic polynomial so you will have to use the quadratic equation to solve for x

OpenStudy (anonymous):

Do you remember the quadratic equation?

OpenStudy (anonymous):

no im sorry

OpenStudy (anonymous):

\[x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

OpenStudy (anonymous):

\[ax^2+bx+c\]

OpenStudy (anonymous):

That is the form that your polynomial is in

OpenStudy (anonymous):

so how do i solve it?

OpenStudy (anonymous):

You use the values of a, b, and c in your quadratic equation and plug thenm into the quadratic formula

OpenStudy (anonymous):

ok, hold on a sec.

OpenStudy (anonymous):

x=-10+ then the symbol 10^2-4, thats all can figure out..

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