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Biology 13 Online
OpenStudy (anonymous):

https://media.glynlyon.com/g_geo_2013/5/groupi73.gif

OpenStudy (anonymous):

Sweet a triangle. Now what? @taylor_propst

OpenStudy (anonymous):

a = 5, b = 10, c =

OpenStudy (deepika.comet):

A[square] +B[square] = C[square]

OpenStudy (abhisar):

root 125

OpenStudy (deepika.comet):

yes root

OpenStudy (deepika.comet):

@taylor_propst we have given you a clue try to calculate it yourself my friend...! we will be here to help you...

OpenStudy (anonymous):

Okay. Write is out the way it should be so I understand better

OpenStudy (abhisar):

\[5^{2} + 10^{2} = 125(c ^{2})\]

OpenStudy (abhisar):

Therefore, c = 11.18

OpenStudy (deepika.comet):

\[\sqrt{a ^{^{2}}}+\sqrt{b ^{2}}=\sqrt{c ^{2}}\] try it now

OpenStudy (deepika.comet):

@Abhisar why did you give the answer. let him try..

OpenStudy (anonymous):

I'm a girl.... but okay.

OpenStudy (deepika.comet):

oh...! sorry my friend.

OpenStudy (anonymous):

Oh its okay my friend

OpenStudy (anonymous):

That's not how it's set up though...

OpenStudy (abhisar):

@deepika.comet it's okay she must be hvng other questn based on pyth. thrm... I am sure she can do by herself now. Can you @taylor_propst

OpenStudy (anonymous):

a = 5, b = 10, c =

OpenStudy (anonymous):

yeah that's what it is. Im getting the answer you guy's are. But I can't put it in like that

OpenStudy (deepika.comet):

AS abhisar told 52+102=125(c2) and then root of 125

OpenStudy (deepika.comet):

the answer is 11.18

OpenStudy (anonymous):

I am getting the answer you guy's are. I can't put it in the problem like that because I don't have a 1

OpenStudy (deepika.comet):

whats your problem exactly make it clear i cant get you

OpenStudy (abhisar):

Suppose c =25, and a=3 . Thhen can you find b ? @taylor_propst

OpenStudy (anonymous):

a = 5, b = 10, c =

OpenStudy (anonymous):

For the right triangle shown, the lengths of two sides are given. Find the third side. Leave your answer in simplified, radical form.

OpenStudy (anonymous):

That is what the question says

OpenStudy (deepika.comet):

c=11.18

OpenStudy (deepika.comet):

simple ....

OpenStudy (anonymous):

I can not put a 1!!!!!!!

OpenStudy (deepika.comet):

a 1 ?

OpenStudy (abhisar):

@shreehari499

OpenStudy (abhisar):

@taylor_propst chck out nw

OpenStudy (anonymous):

If we want to keep it nice and simple and not write a long list of numbers for the answer, we can just simplify the root, \[\sqrt{125}\], to \[5\sqrt{5}\] @taylor_propst

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