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OpenStudy (anonymous):
Sweet a triangle. Now what? @taylor_propst
OpenStudy (anonymous):
a = 5, b = 10, c =
OpenStudy (deepika.comet):
A[square] +B[square] = C[square]
OpenStudy (abhisar):
root 125
OpenStudy (deepika.comet):
yes root
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OpenStudy (deepika.comet):
@taylor_propst we have given you a clue try to calculate it yourself my friend...!
we will be here to help you...
OpenStudy (anonymous):
Okay. Write is out the way it should be so I understand better
OpenStudy (abhisar):
\[5^{2} + 10^{2} = 125(c ^{2})\]
OpenStudy (abhisar):
Therefore, c = 11.18
OpenStudy (deepika.comet):
\[\sqrt{a ^{^{2}}}+\sqrt{b ^{2}}=\sqrt{c ^{2}}\]
try it now
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OpenStudy (deepika.comet):
@Abhisar why did you give the answer.
let him try..
OpenStudy (anonymous):
I'm a girl.... but okay.
OpenStudy (deepika.comet):
oh...! sorry my friend.
OpenStudy (anonymous):
Oh its okay my friend
OpenStudy (anonymous):
That's not how it's set up though...
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OpenStudy (abhisar):
@deepika.comet it's okay she must be hvng other questn based on pyth. thrm... I am sure she can do by herself now. Can you @taylor_propst
OpenStudy (anonymous):
a = 5, b = 10, c =
OpenStudy (anonymous):
yeah that's what it is. Im getting the answer you guy's are. But I can't put it in like that
OpenStudy (deepika.comet):
AS abhisar told 52+102=125(c2) and then root of 125
OpenStudy (deepika.comet):
the answer is 11.18
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OpenStudy (anonymous):
I am getting the answer you guy's are. I can't put it in the problem like that because I don't have a 1
OpenStudy (deepika.comet):
whats your problem exactly make it clear i cant get you
OpenStudy (abhisar):
Suppose c =25, and a=3 . Thhen can you find b ? @taylor_propst
OpenStudy (anonymous):
a = 5, b = 10, c =
OpenStudy (anonymous):
For the right triangle shown, the lengths of two sides are given. Find the third side. Leave your answer in simplified, radical form.
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OpenStudy (anonymous):
That is what the question says
OpenStudy (deepika.comet):
c=11.18
OpenStudy (deepika.comet):
simple ....
OpenStudy (anonymous):
I can not put a 1!!!!!!!
OpenStudy (deepika.comet):
a 1 ?
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OpenStudy (abhisar):
@shreehari499
OpenStudy (abhisar):
@taylor_propst chck out nw
OpenStudy (anonymous):
If we want to keep it nice and simple and not write a long list of numbers for the answer, we can just simplify the root, \[\sqrt{125}\], to \[5\sqrt{5}\]
@taylor_propst