Question

What are the excluded values? y+5/y^2+4y-32

Answer 1

Does it look like this exactly? http://www5a.wolframalpha.com/Calculate/MSP/MSP1502098f6ad2d6ic30900000fd5ff28g3id0481?MSPStoreType=image/gif&s=40&w=114.&h=40.

Answer 2

its, . y = 4 and -8

Answer 3

@cillawilla

Answer 4

How do you know? ^ it could also look like this: http://www4c.wolframalpha.com/Calculate/MSP/MSP5421h9ca826age07dd100004hbb3f0i7hef4e9i?MSPStoreType=image/gif&s=30&w=106.&h=40.

Answer 5

they need the excluded values right? It would be either, that what i said or -8 , 4

Answer 6

y^2 + 4y - 32 = 0
(y + 8)(y - 4) = 0
y + 8 = 0 or y - 4 = 0
y = -8...........y = 4

The excluded values are -8 and 4.

Answer 7

Or it could look like this: http://www4c.wolframalpha.com/Calculate/MSP/MSP988220e529431652hga400001b172beeibc1fedb?MSPStoreType=image/gif&s=54&w=89.&h=40.

You can't know for sure until the person asking the question clears it up a little.

Answer 8

yeah but they are off line. so guess what

Answer 9

We are both right! :D

Answer 10

I didn't give a solution yet, I only brought up a question.

Answer 11

we dont know what they are asking until more in depth description.

Answer 12

Yep ^