Question

p^2+14p-15=0

Answer 1

I just wanna know the answer lol

Answer 2

I got p=-15 and p=1

Answer 3

but im not sure

Answer 4

what about (t+2)^2=4 ?

Answer 5

I got t=-4 and t-0, but im not the best at math

Answer 6

p^2+15p-p-15=0
p(p+15)-(p+15)=0
(p-1)(p+15)=0

Answer 7

p=1,-15

Answer 8

I met t=-4 and t=0

Answer 9

x^2-7x+12=0 ?

Answer 10

do u know any website that will just give u the answer for these questions ?

Answer 11

x^2-4x-3x+12=0
(x-4)(x-3)=0
x=,3

Answer 12

yeah, someone jus got nasty with me for posting it lol http://www.wolframalpha.com/input/?i=+%28t%2B2%29%5E2%3D4+%3F

Answer 13

thanks angelbaby_2434

Answer 14

but it show how to do it to and it helped me so hope it help =)

Answer 15

okay ..um ...what is the square of the sum of a number and 3 is 16...but there is 2 solutions

Answer 16

is that the whole question?

Answer 17

yea that's the whole question

Answer 18

Lets call the number we are looking for "x".

Your statement in math symbols would be:
(x+3)^2 = 16

square (x+3):
x^2+6x+9=16

subtract 16 from each side:
x^2+6x-7=0

factor:
(x+7)(x-1)=0

Now either (x+7)=0 OR (x-1)=0

So x=-7 OR 1

Answer 19

(x+3)^2 = 16
(x+3)(x+3) = 16
x^2 + 6x + 9 = 16
after subtracting 16 from each side you get...
x^2 + 6x - 7 = 0
(x+7)(x-1) = 0
so either (x+7) = 0, or (x-1)=0
x+7 = 0
x+7-7 = 0-7
x = -7
or x-1 = 0
x-1+1 = 0+1
x = 1
so...
x = -7 or x = 1

Answer 20

IDK is that right?