Question

secAsinA / tanA + cotA = sin^2A

Answer 1

I dont think theres a solution

Answer 2

secAsinA / (tanA + cotA)
=secAsinA /( sinA/cosA + cosA/sinA)
= secAsinA( (sin^2A+cos^2A)/(sinAcosA) )
=secAsinA* (sinAcosA)/ (sin^2A+cos^2A)
= sinA*sinA =sin^2A [ as secA cosA=1 and sin^2A+cos^2A=1 ]

Answer 3

Thanks matricked. i thought we were solving for A, but this a a prove LHS=RHS problem.
no thanks to honai

Answer 4

yw