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Which cosine function has a maximum of 2, a minimum of -2, and a period of 2pi/3? y=3cos2(theta) y=2cos(2theta)/(3) y=2cos3(theta) y=2cos(theta)/(3)
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@hartnn
@johnweldon1993
Amplitude = A = 2 is given Period T = 2pi/3 use the general form of cos function : \(\Large y = A \cos (\dfrac{2\pi}{T}\theta )\)
So it would be 2 cos 2theta/3?
how did you get 2theta/3 ?? 2pi/T with T =2pi/3 gives 2pi/(2pi/3) = ... ?
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I entered it into my calculator. But 2pi/2pi/3 is 3
yes, 3 is correct!
y=2cos3(theta)
Ohh okay! Thank you! :) These are difficult for me. I've been practicing a little more.
good! keep practicing :) welcome ^_^
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