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Mathematics 10 Online
OpenStudy (anonymous):

differentiate: e^(2x) * sin2x * cos x

OpenStudy (anonymous):

is the 2x*sinx*cosx whole in the exponent or only 2x

OpenStudy (anonymous):

just 2x

OpenStudy (anonymous):

( 2e^(2x)sin2x + e^(2x)cos2x )* cosx + ( -sinx ) (e^(2x) sin2x)

OpenStudy (anonymous):

can u tell me how u got that?

OpenStudy (anonymous):

group 2 terms together and use product rule use chain rule wherever needed and simplify

OpenStudy (anonymous):

then product rule again? the resultant and the leftover value?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

hmm k, ty

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