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OpenStudy (anonymous):
A package contains 10 candy canes, 5 of which are cracked. If 3 are selected, find the probability of getting no cracked candy canes.
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OpenStudy (anonymous):
The probability would be 3/5
OpenStudy (anonymous):
There are 5 uncracked canes and 5 cracked so the 5 u cracked would be the denominator. If umpickex 3 the numerator would be 3 so the answer is 3/5 or 3:5 in a ratio
OpenStudy (anonymous):
my choices are A.0.2870 B.0.3852 C.0.0833 D.0.1938
OpenStudy (anonymous):
O.o the probabiltys have to b in decimal form?
OpenStudy (anonymous):
yes
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