Question

sin x = sqrt2/2

Answer 1

You need to construct a triangle and find where the sin is sq rt 2 over 2. This would be a 45 45 90 triangle. The hypotenuse is sq rt of 2 and the side opposite is 1. You have to rationalize the denominator to get the sq rt of 2 over 2, but the "x" is 45 degrees or pi/4