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A charge q of 1.3 × 10-16 coulombs moves from point A to a lower potential at point B in an electric field of 3.2 × 102 newtons/coulomb. If the distance traveled is parallel to the field is 1.1× 10-2 meters, what is the difference in the potential energy?
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1.3 x 3.2 x 1.1 x 10-16 J
Thanks naveenbabbar...only a 8 hours late but ur help is still appreciated! :)
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