Question

Which of the following is the equation of a line perpendicular to
12y = 3x + 5 that passes through (-1, 1)

Answer 1

First find the slope of the equation 12y = 3x+5
divide the equation by 12.
y =( 3/12)x+5/12
slope m = 3/12 = ¼
the line perpendicular will have slope m = -4
equation of the line passing through the point ( -1,1)
(y-y1) = m(x-x1)
(y-1) = -4 (x-(-1) )
(y-1) = -4(x+1)
y-1 = -4x-4
y = -4x-4+1
y = -4x-3

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