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OpenStudy (anonymous):
Help ...? EF is the midsegment of trapezoid ABCD. Determine the value of x??
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OpenStudy (anonymous):
OpenStudy (anonymous):
A. 8.2
B. 3.8
C. 5
D. 10.7
OpenStudy (anonymous):
@love14 what do you think the first step is
OpenStudy (anonymous):
the midsegment has average length of the other two sides, so 8.8 is the average value of 12.6 and x. can you find x from here?
OpenStudy (jdoe0001):
\(\bf \textit{midsegment of a trapezoid}=\cfrac{1}{2}(base1+base2)\qquad thus
\\ \quad \\
EF=\cfrac{1}{2}(DC+AB)\implies 8.8=\cfrac{1}{2}({\color{brown}{ x}}+12.6)\)
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OpenStudy (anonymous):
I think its C.
OpenStudy (anonymous):
I tried, the options listed for the equation, and none so far give me 8.8? :(
OpenStudy (anonymous):
Wait nvm, I got 5 :)
OpenStudy (anonymous):
@love14 you are solving the wrong equation. it should be
\[ \frac{12.6 + x}{2} = 8.8 \]
OpenStudy (anonymous):
12.6 + X which is 5. Divided by 2 = 8.8. Did you try it like that?
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OpenStudy (anonymous):
Thank you guys ! :))
OpenStudy (anonymous):
Np! Always here to help. :3
OpenStudy (anonymous):
Thanksss ;D
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