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What is the simplified form of 9g^2h^8 over 6g^5h^4?
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subtract the exponents of the like terms
how?
\[\frac{9g^2h^8}{6g^5h^4}\] \[\frac{3h^{8-4}}{2g^{5-2}}\] is a start
i assume "how" means "what" i am positive you know how to subtract.
ok calm down
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you good from there?
oh ok thank you, yah i do i was just confused :)
yes :)
yw
so the answer would be 3h^4 over 2g^3?
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