A camera and case together cost $110. If the camera cost $100 more than the case, how much does the case cost? Explain your answer and the steps taken to get the answer. Give your best constructed response answer.
10 dollars.
Well then the case would cost 10 dollars
because the camera is 100 dollars more
it's just 110-100. lol
so 110-100
= 10
get it
how come i dont get a medal and i answered your question whatever!
Im not sure, but to have a difference of 100, x=camera y=case x=100+y x-y=100, there is many ways to solve this, but lets keep it simple, if it was, x=100 and y =10 then x-y=90, so its false, now if x=105 and y=5, then x+y=110 and x-y=100. So the case costs 5 and the camera 105. I might sound stupid, but hey, im just a junior high school student from Greece xD.
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