I need help. I have done all of the steps I am just having a hard time with the signs.
Find the area bounded by 2/x and x+y=3
the integral from 1 to 2 of x+y=3
=y+3/2
The integral from 1 to 2 of 2/x= ln(4)
(y+3/2)-(ln(4)=
(-y+3/2)-(+2ln(2))
Would my answer be
3/2-2ln(2) or 3/2 +2ln(2)

Question

I need help.  I have done all of the steps I am just having a hard time with the signs.  
Find the area bounded by 2/x and x+y=3
the integral from 1 to 2 of x+y=3
=y+3/2
The integral from 1 to 2 of 2/x= ln(4)
(y+3/2)-(ln(4)=
(-y+3/2)-(+2ln(2))
Would my answer be 
3/2-2ln(2) or 3/2 +2ln(2)

anonymous · Answer

Refer to the Mathematica solution attached.