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Verify the identity cotx-tanx all over cot^2x- tan^2x= sinxcosx
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How would you go to factor ( cot^2x- tan^2x)? Factoring this will make your life much easier.
(cotx-tanx)/(cot^2x- tan^2x) =(cotx-tanx)/ ( (cotx-tanx) * (cotx+tanx) ) =1/(cotx+tanx)
1/( (cosx/sinx) + (sinx/cosx) ) =1/ ( (cos^2x+ sin^2x) / (cosx*sinx) ) = cosx*sinx/(cos^2x+ sin^2x) = cosxsinx as we know (cos^2x+ sin^2x)=1
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