how do i show triangle BEF is equilateral Given : AB = AD http://www.webpagescreenshot.info/img/537de1eb128444-02939013
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yes, but A is center of top triangle and D is center of bottom triangle
so ur picture is bit misleading
ic , i dint note that was given
oh sorry, i stumbled on this question while going thru some other question; here are the givens : 1) AB = AD 2) AB is radius of top circle 3) AD is radius of bottom circle Prove BEF is equilateral
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yes this is looking good :)
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u can conclude this as a beginning |dw:1400759334121:dw|
can u just briefly show why it will be perpendicular
next step , by SAS BF=BE
sure :)
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any point A |dw:1400759553316:dw|
okay
lolz forget abt step by step ill wrote down the theory :D
okay anything is fine :)
first join EA and AF and ED and DF now we need to first show tht AD and EF bisect each other .. then the rest can be proved...
and its more like this http://www.onlinemathlearning.com/perpendicular-bisector.html
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