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Mathematics 11 Online
OpenStudy (rational):

how do i show triangle BEF is equilateral Given : AB = AD http://www.webpagescreenshot.info/img/537de1eb128444-02939013

OpenStudy (anonymous):

|dw:1400758909297:dw|

OpenStudy (rational):

yes, but A is center of top triangle and D is center of bottom triangle

OpenStudy (rational):

so ur picture is bit misleading

OpenStudy (anonymous):

ic , i dint note that was given

OpenStudy (rational):

oh sorry, i stumbled on this question while going thru some other question; here are the givens : 1) AB = AD 2) AB is radius of top circle 3) AD is radius of bottom circle Prove BEF is equilateral

OpenStudy (anonymous):

|dw:1400759127875:dw|

OpenStudy (rational):

yes this is looking good :)

OpenStudy (anonymous):

|dw:1400759240700:dw|

OpenStudy (anonymous):

u can conclude this as a beginning |dw:1400759334121:dw|

OpenStudy (rational):

can u just briefly show why it will be perpendicular

OpenStudy (anonymous):

next step , by SAS BF=BE

OpenStudy (anonymous):

sure :)

OpenStudy (anonymous):

|dw:1400759530347:dw|

OpenStudy (anonymous):

any point A |dw:1400759553316:dw|

OpenStudy (rational):

okay

OpenStudy (anonymous):

lolz forget abt step by step ill wrote down the theory :D

OpenStudy (rational):

okay anything is fine :)

OpenStudy (anonymous):

first join EA and AF and ED and DF now we need to first show tht AD and EF bisect each other .. then the rest can be proved...

OpenStudy (anonymous):

http://www.mathopenref.com/constperpextpoint.html

OpenStudy (anonymous):

and its more like this http://www.onlinemathlearning.com/perpendicular-bisector.html

OpenStudy (rational):

|dw:1400760205355:dw|

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