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Find the image of A(6, -4) after it is reflected over the line y = - 2, then reflected over the line x = 1. (-4, 6) (-4, 0) (-4, -4) (6, 2)
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The point (6, -4) is 2 units below the line y = -2. Hence on reflection in the same line it becomes (6, -4+4) = (6, 0). Then the point (6, 0) is 5 units right of x = 1 so after reflection in the same it becomes (6 - 10,0) = (-4,0) I would go with option B
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