What are the coordinates of the vertices of a triangle A'B'C' that results from a translation of triangle ABC two units down?

https://media.glynlyon.com/g_geo_ccss_2013/14/geo_13_1_assess_media_11.gif

A'(0, 1) B'(4, 0) C'(-3, -2)
A'(-2, 1), B'(2, 0) C'(-5, -6)
A'(-4, 3), B'(0, 2), C'(-7, -4)
A'(-2, 5), B'(2, 4), C'(-5, -2)

Question

What are the coordinates of the vertices of a triangle A'B'C' that results from a translation of triangle ABC two units down?

https://media.glynlyon.com/g_geo_ccss_2013/14/geo_13_1_assess_media_11.gif

A'(0, 1) B'(4, 0) C'(-3, -2)
A'(-2, 1), B'(2, 0) C'(-5, -6)
A'(-4, 3), B'(0, 2), C'(-7, -4)
A'(-2, 5), B'(2, 4), C'(-5, -2)

anonymous · Answer

@dannyrod2000 @minoz

anonymous · Answer

here since we are shifting up 2 units, only y axis is increased by 2 units, x remains same

dannyrod2000 · Answer

it is probably A'(-2, 1), B'(2, 0) C'(-5, -6) do you think @minoz