Question

.

Answer 1

f(x) = tan(4x − π)=-tan(pi-4x)=tan4x ok??

Answer 2

now tan4x=sin4x/cos4x
now for finding asymptotes
equate cos4x=0
s0
\[4x=\frac{ (2n+1)*\pi }{ 2}\]
ok so far??

Answer 3

so now
\[x=\frac{ (2n+1)\pi }{ 8 }\]
now put n=1,2,3,......
and u can find asymptotes between pi/4 to 5pi/4