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Mathematics 8 Online
OpenStudy (muzzack):

Help :)

OpenStudy (muzzack):

OpenStudy (muzzack):

\[(\sqrt{2})(^{3} \sqrt{2})\]

OpenStudy (muzzack):

can anybody help @Ashleyisakitty @Australopithecus @amistre64 @phi @dacutiepie @timo86m @wio @victoria_lion @beccaboo333

OpenStudy (anonymous):

\[\sqrt{2}=2^{1/2}\] \[\sqrt[3]{2}=2^{1/3}\] \[x^{a}x^{b} = x^{ab}\]

OpenStudy (muzzack):

ohh makes sense so it would be \[2^{\frac{ 1 }{ 2}\times \frac{ 1 }{ 3 }}\]

OpenStudy (muzzack):

\[2^{\frac{ 1 }{ 6 }}\]

OpenStudy (muzzack):

so it would be A

OpenStudy (muzzack):

thx @mtbender74

OpenStudy (anonymous):

np

OpenStudy (muzzack):

your wrong

OpenStudy (muzzack):

its\[2^{\frac{ 5 }{ 6 }}\]

OpenStudy (muzzack):

@mtbender74

OpenStudy (muzzack):

its\[2^{\frac{ 1 }{ 2}+\frac{ 1 }{ 3 }}\]

OpenStudy (muzzack):

@mtbender74 @mtbender74 @mtbender74

OpenStudy (anonymous):

oops...sorry...for some reason my brain hiccupped... i'm going to blame being sick the past 3 days..

OpenStudy (anonymous):

\[x^{a}x^{b} = x^{a+b}\] \[(x^{a})^{b} x^{ab}\]

OpenStudy (muzzack):

lol its okay :)

OpenStudy (muzzack):

but you had the concept

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