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A parallelogram is drawn with a 60 degree angle as marked. Find the height of the parallelogram.
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are you familiar with trigonometric identities?
no
I think you can solve this one using parallelogram identities but I am not familiar with these.
A good way to solve this one is to take the left side as a separate triangle.
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|dw:1400890669927:dw|
\[\sin \theta = opp/ hyp\]
\[\sin 30 = opp/ 3\]
opp = 3 sin 30
so the answer is 3/2
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Do you add it on to the other part of the problem?
to the 5?
or is the answer just 3/2?
nvm thank you :)
You welcome :) Glad to help.
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