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Find the 5th term of (x-1)^7
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use the binomial theorem
yes, I posted the steps to solving with the binomial theorem in the last question you asked. I can help guide you through it if you'd like
I just need help on the exponents for (x) and (-1) So far I have 7 C 4 (x) (-1)
\[(a+b)^n= \sum_{i=0}^{n}\left(\begin{matrix}n \\ i\end{matrix}\right)n^{n-i}b^i\]
review Pascal's Triangle so you will see the pattern
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Okie thanks
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