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WILL REWARD!! What are the restrictions on the variable -(x+1) / (x-1) (x+3)
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check to see where your function is undefined. This will be where the denominator is equal to zero. These will be the 'zeros' of your funtion
so see where x-1=0 and where x+3=0
Yes i do.
so now solve both for x and see what values you get. These two values will be part of the retrictions within your boundary
1 and -3 are the only two restrictions
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