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Mathematics 13 Online
OpenStudy (anonymous):

WILL REWARD!! What are the restrictions on the variable -(x+1) / (x-1) (x+3)

OpenStudy (anonymous):

check to see where your function is undefined. This will be where the denominator is equal to zero. These will be the 'zeros' of your funtion

OpenStudy (anonymous):

so see where x-1=0 and where x+3=0

OpenStudy (anonymous):

Yes i do.

OpenStudy (anonymous):

so now solve both for x and see what values you get. These two values will be part of the retrictions within your boundary

OpenStudy (anonymous):

1 and -3 are the only two restrictions

OpenStudy (anonymous):

correct

OpenStudy (skullpatrol):

Do you understand why @mrivera3113 ?

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