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Mathematics 15 Online
OpenStudy (anonymous):

Algebra II someone check my answers

OpenStudy (anonymous):

OpenStudy (anonymous):

@sourwing @satellite73 @jim_thompson5910 @HelpBlahBlahBlah

OpenStudy (anonymous):

9 is wrong

OpenStudy (anonymous):

It is then A right?

OpenStudy (anonymous):

\[(1-\cos(x))(1+\cos(x))=1-\cos^2(x)=\sin^2(x)\]

OpenStudy (anonymous):

and \[\sqrt{\frac{\sin^2(x)}{\cos^2(x)}}=\sqrt{\tan^2(x)}\]

OpenStudy (anonymous):

jeez another bad question \[\sqrt{\tan^2(x)}=|\tan(x)|\]not \(\pm\tan(x)\) who is writing this stuff?

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