Question

-a2 - 3b3 + c2 + 2b3 - c3 if a=3,b=2,c=-3

Answer 1

Can you please snapshot the source of the question cause its quite ambigous

Answer 2

-3x2-3x2x3+(-3x2)+2x2x3-(-3x3)
-6-18-6+12+9
-30+21
-9

Answer 3

I think the 2 after the variables is the square and , the three is the cube

Answer 4

If a = 3 , b = 2 and c = -3 . -a^2 - 3b^3 + c^2 + 2b^3 - c^3
Will become -3^2 - 3(2)^3 + -3^2 + 2(2)^3 + 3 ^ 3

Answer 5

9 - 24 +9 + 16 + 9 = 1