Question

Locate the center of the circle with the equation, 3x^2+3y^2-6x+2y-14=0

Answer 1

Try to make this equation into the form of : (by dividing 3 both sides)

\(x^2 + y^2 + 2gx + 2fy + c = 0\)

As the centre is \(\equiv (-g,-f)\) .

Solve, for g and f by comparing the equations.

Answer 2

thank you my answer is (1,-1/3) is it correct ? :)

Answer 3

Yeah, that seems correct to me.