WILL REWARD!! What values for theta(0<_theta<_2pi) satisfy the equation? 2 sin theta cos theta + sqrt3 cos theta=0 A. pi/2, 4pi/3, 3pi/2, 5pi/3 B. pi/2, 3pi/4, 3pi/2, 5pi/3 C. pi/2, 3pi/4, 3pi/2, 5pi/4 D. pi/2, pi/4, 3pi/2, 5pi/3
A. pi/2, 4pi/3, 3pi/2, 5pi/3
How did you get that?
Just a second...
Is the sqrt(3) separate or with the cos(theta)? This is important. I calculated my result with the cos(theta) not with the sqrt(3)
Got it. Just a second...
It is a lot of steps.
Are you a 100% positive that is the answer?
@Blank
Yes, I'm positive that the answer is A. A. pi/2, 4pi/3, 3pi/2, 5pi/3 I checked with an online calculator. http://www.wolframalpha.com/input/?i=2+sin+theta+cos+theta+%2B+sqrt3+cos+theta%3D0+%2C+%280%3Ctheta%3C2pi%29
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