Question

help?

Answer 1

You know that angle abd must be 45 degrees since it is perfectly split at a right angle

Answer 2

\[\sin(45)=\frac{ AD }{ 10 }\rightarrow 10\sin(45)=AD\]
\[AD=\frac{ \sqrt{2} }{ 2 }10\]
\[=5\sqrt{2}\]
\[\sin(adb)=\frac{ 5\sqrt{2} }{ 10 }=\frac{ \sqrt{2} }{ 10 }\]

Answer 3

oops that should be AB not AD but it still works out the same