Question

Factor completely.

9j^2 - 25m^12
(9j + 5m^6) (9j - 5m^6)
cannot be factored
(9j - 5m^6)^2
(3j + 5m^6) (3j - 5m^6)

Answer 1

(3j-5m^(6))(3j+5m^(6))

The answer is D.

Answer 2

The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).

Answer 3

Hope this helps. :)