Question

solve
y=x^2-4x+3
y=2x-2

Answer 1

There is two solutions:
x=1,y=0
x=5,y=8

Answer 2

(1, 0)
and
(5, 8)

Answer 3

Tell me if you need the steps.

Answer 4

yes please i would like to understand this more

Answer 5

Just a second...

Answer 6

y=x^(2)-4x+3
y=2x-2

Since the equation was solved for y, replace all occurrences of y in the other equations with the solution (x^(2)-4x+3).
y=x^(2)-4x+3
x^(2)-4x+3=2x-2

Move all terms not containing x to the right-hand side of the equation.
y=x^(2)-4x+3_
x^(2)-6x+3=-2

To set the left-hand side of the equation equal to 0, move all the expressions to the left-hand side.
y=x^(2)-4x+3
x^(2)-6x+5=0

Factor the trinomial x^(2)-6x+5.
y=x^(2)-4x+3
(x-1)(x-5)=0

Set each of the factors of the left-hand side of the equation equal to 0.
y=x^(2)-4x+3
x-1=0
x-5=0

Since -1 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 1 to both sides.
y=x^(2)-4x+3
x=1
x-5=0

Set each of the factors of the left-hand side of the equation equal to 0.
y=x^(2)-4x+3
x=1
x-5=0

Since -5 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 5 to both sides.
y=x^(2)-4x+3
x=1
x=5

The complete solution is the set of the individual solutions.
y=x^(2)-4x+3
x=1,5

Expand the exponent (2) to the expression.
For x=1
y=(1)-4(1)+3

Multiply -4 by each term inside the parentheses.
For x=1
y=(1)-4+3

Add 3 to -3 to get 0.
For x=1
y=0

Squaring a number is the same as multiplying the number by itself (5*5). In this case, 5 squared is 25.
For x=5
y=(25)-4(5)+3

Multiply -4 by each term inside the parentheses.
For x=5
y=(25)-20+3

Add 3 to 5 to get 8.
For x=5
y=8

The final solution is the set of all solutions.
x=1,y=0
x=5,y=8

Hope this helps. I used the Substitution method here.

Answer 7

thank you this helped alot