Question

Please help write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

y = four thirds x + 8

y = four thirds x + 3

y = -three fourths x + 8

y = -three fourths x + 3

Answer 1

Two parallel lines have same slope.
Hence, we find the slope of given line.
Equation of line in slope-intercept form : y = mx+c
We get: y= (4/3)x + 4 . Hence, slope = 4/3 which is also the slope of any line which is parallel to the given line.
Our required line is : y= (4/3)x + C
Now put the given point (-3, 4), through which this line passes, in the equation.
4 = (4/3) * -3 + C
This gives C=8
Hence required equation is y = (4/3)x + 8