Question

A researcher tagged 40 giant turtles in 2008. In 2009, she returned and captured 50 turtles, 16 of which were tagged. In 2010, she returned again and captured 30 turtles, 8 of which were tagged.

a. Use a proportion to estimate the turtle population for 2009.

b. Use a proportion to estimate the turtle population for 2010.

Answer 1

@wifibasedgod

Answer 2

i kinda forgot proportions (:|) (._.) (|:) (.-.)

Answer 3

sorey

Answer 4

help @kx2bay please

Answer 5

@ganeshie8 help

Answer 6

oh wait

Answer 7

its almost 2:00

Answer 8

i remember this now

Answer 9

they ask to write a fraction

Answer 10

ok

Answer 11

http://www.mathsisfun.com/algebra/proportions.html

Answer 12

50 turtles to 30 turtles translates to 5/3 (five over three) and 16 tagged turtles to 8 tagged turtles translates to 2/1 (two over one).

Answer 13

can you solve from here?

Answer 14

look at first reply for long answer, and second reply for short :
https://in.answers.yahoo.com/question/index?qid=20130517082822AANJESo

Answer 15

this is capture -recapture and is a application of ratios


let p = population estimate


2009

its modelled by Population/tagged = recatpure pop/tagged

\[\frac{P}{40} = \frac{50}{16}\]

just solve for P

Answer 16

for 2010

use

\[\frac{P}{40} = \frac{30}{8}\]

again, solve for P

Answer 17

ok

Answer 18

is \[\frac{ P }{ 40 }\] = \[\frac{ 30 }{ 8 }\] like the formula?