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Probability 52 Online
OpenStudy (anonymous):

Question

OpenStudy (anonymous):

OpenStudy (anonymous):

is my answer correct for a , b , and c

OpenStudy (anonymous):

waiting for help...

OpenStudy (sidsiddhartha):

k=4/3 so \[ P(0.3< X < 0.6) =\int\limits_{0.3}^{0.6}4/3*x ^{1/3}\] ans is 0.305 i think this is correct

OpenStudy (anonymous):

nice ... that's good but what about b? is it correct

OpenStudy (sidsiddhartha):

yeah it lookd like F(x)=0 for x<0 =x^4/3 for 0<x<1 =1 for x>1 i think this should be the cumulative distribution function

OpenStudy (anonymous):

thank you very much brother sidsiddhartha for help i wish for you best things...

OpenStudy (sidsiddhartha):

:) no problem

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